Algebra Discussion, Essay Example

Suppose the number of cars on the 1^st avenue of a city (C) is related with the time i.e. number of days (t) such as C = p*(a^t); where “a” is the growth factor and “p” is the number of cars recorded on the first day.

Now, let p = 150 and a = 0.7

So now the above equation becomes C = 150*(0.7^t).

Now the numbers of cars on the 1^st avenue i.e. “C” can be determine after 5 days,10 days and after 15 days respectively by putting t = 2,t = 5 and t = 8 in the above formula.

So, number of cars on 1^st avenue after 2days is = 150*(0.7^2) = 73(approx)

So, number of cars on 1^st avenue after 5 days is = 150*(0.7^5) = 25(approx)

So, number of cars on 1^st avenue after 8 days is = 150*(0.7^8) = 8(approx)

Summary

According to the previous results we get that the   number of cars on the 1^st avenue is strictly decreasing with the time. That means as the time passes that number decreases. No, I’ll not want to commute work every day on the road because the number of cars is decreasing day by day.