Interpreting the Test Scores, Essay Example

In interpreting the test scoreswe must follow the manual of standardized test scores to find the correct method to interpret the scores properly and to keep in mind that the manual is designed for evaluators to look for criterions to make the best decision on the scoring process because we rely on data accuracy in order to find the relevance across literatures. For instance, those students who answered Letter E the most are taken into consideration as the continuous variables whereas other letters A, B, C,D are the dichotomous variables. Even though, we do not know the item point system for each question and the correct score to make a difference in necessary order. There are three Pt biserial numbers are in negative while the other two are in the positive, that is the letter A and E. Obviously, the learners felt that it is the best answer to score. It is not only based on the learners who scored the highest, it is based on the average of learners who do not have the intention to score the answers incorrectly. The values above which fall 50% of the scores and below which fall 50% of the scores would represent the 50% percentile (Oermann, et al. 2014).The mean average score is 66.8 and the median score is 33.4 and the standard deviation is 0.76. The characteristics of coefficient biserials showed us that there is some difficulty in correlating all of the ranges in place to find the skewness which lead us to examine further and find out that the outliner shape of the modality distribution have been skewed because of the given scores that are far off from the normal linear line. Obviously, the scores could not be normally distributed as we want it to occur. Thenwe get to be concerned on whether the scores are the criterion –referenced lowest scores in orderto find a variable that could tell us  one of the four reasons for the cause for this frequency distribution that has occurred would be the (2) Distracters are too easy to eliminate (Oermann, et al, 2014). As we know that there are N= 334 learners who undertook the examination and that in average the power of critical value is P=0.34 with approximately 29 degrees of freedom as accorded to the two-tailed tests chart. This result tells us that in national average, there are approximately 29 learners who scored the same numbers has also checked off the same multiple choice answers of the given questions.

References

Oermann, M. H., &Gaberson, K. B. (4th Ed.). (2014). Evaluation and testing in nursing education. New York: Springer. Chapters 10-12.