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Density and Archimedes Principle, Lab Report Example

Pages: 3

Words: 753

Lab Report

Introduction

The principle introduced by Archimedes delineates that for bodies that are proportionally or comprehensively submerged in a liquid, there is an equal and opposite force which is equivalent to the weight of the body that is displaced. The mass of an object responds in a downward manner and the force of buoyancy that is provided responds in an upward manner. The mass of the fluid displaced has a mass of W = mg. The weight can de discovered in the context of the density and the volume which is equivalent to m = ρV, where the object’ density ρ can be encountered. All densities are applicable under Archimedes principle. In the event that the density of an object is superior to that of the fluid, the object will experience a downward force and will sink. in the event that the density of the object is equivalent to that of the liquid, the object will remain afloat.

As a solid object is submerged in a fluid, the volume of liquid displaced is equivalent to its own volume. As the displaced fluid had been in a state of equilibrium with the fluid in which it was submerged prior to displacement, the buoyant force that is exercised on the fluid is equivalent to its proprietary weight and an equivalent force will be placed on the floating object. The force of buoyancy placed on an object is not reliant on the objects co0mposition. Consequently, the force of buoyancy is usually equivalent to the volume of the fluid displaced. Consequently, the statement of Archimedes principle is expressed:

  • An object that is completely immersed in a liquid receives a force of buoyancy that is equivalent to the mass of the liquid displaced.
  • The force of buoyancy reacts in a manner vertically upward passing through the position which had been the core of gravity of the liquid which had been displaced

Mass of the liquid displaced = Buoyant force

In the case where

ρ = MV

Consequently, the force of buoyancy is equivalent to Vρg

G 0 The force of gravity = 9.803 m/ s2

ρ = Liquid’s density

V= Mass of the displaced liquid

Experimental procedure

A string had been affixed to an object in a way that the string had been able to support the mass of the object. The object was suspended from a spring scale and the mass had been documented. The scale was calibrated at zero. The object continued to be affixed to the spring scale and the mass was documented free body equation was demonstrated for the object. The mass of the liquid displaced had been compared.

Experimental Procedure part 3

A massive wooden ball was applied. The volume of the ball had been tabulated and the volume of the sphere was assessed by 4/3πr3. The mass of the ball was measured by the amount of water displaced. The volume of the ball was determined to be 5.2 x 10’3 m3

Results

Part 2- Weight of Displaced Liquid

Force Formula Change
1.35 N 2,26 N 0.91 N
1.1 N 1.937 N 0.84 N

Part #

Original = 0.600 l

0.714 g/ m3 = ρ

New volume = 0.650 l

F = ρ Vg = 50 X 10 ‘6 x 1 x 103 x 9.8 m/ s2 = 0.49 N

F = mg = 46.7 x 10’3 x 9.8 m/ s2 = 0.45766 N

Discussion

In accordance with the principle proposed by Archimedes, the resultant buoyant force is equivalent to the displacement of the fluid. As a result, the displacement of the fluid had been applied and confirmed in the tabulation of density, where the assessment of the samples could be evaluated with the displacement of the water as the object had been submerged. The principle proposed by Archimedes could also define the floating ability of an object in water. The objects which become submerged in water should manifest a specific gravity superior to one, in the event that the object has a specific gravity less than one, the object should sink.

Conclusion

As the object is compositely or totally submerged in a liquid, the ingenuity of the buoyant force reacting on the object is equivalent to the mass of the fluid displaced by the object. Consequently, the force of buoyancy is responding in a manner that opposes the mass of the object, considering that the mass of the object submerged in liquid is inferior to the mass in air. The differential manifested between the object’s weight in air and the mass of the object submerged in a liquid is equivalent to the force of buoyancy reacting on the object. In the case of an object completely submerged in a liquid.

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